Let X, Tx, Y and U be given.
Assume HU: U subspace_topology X Tx Y.
We will prove (ambient_open_of_subspace_open X Tx Y U) Tx U = (ambient_open_of_subspace_open X Tx Y U) Y.
We prove the intermediate claim Hex: ∃VTx, U = V Y.
An exact proof term for the current goal is (subspace_topologyE X Tx Y U HU).
An exact proof term for the current goal is (Eps_i_ex (λV : setV Tx U = V Y) Hex).