We will
prove p0 (i6 ⨯ i6) = p0 (- 1).
We will
prove p0 (i6 ⨯ i6) = - 1.
rewrite the current goal using
OSNo_p0_i6 (from left to right).
rewrite the current goal using
OSNo_p1_i6 (from left to right).
rewrite the current goal using mul_HSNo_0L 0 HSNo_0 (from left to right).
We will
prove 0 + - ((- j) ' * (- j)) = - 1.
rewrite the current goal using conj_minus_HSNo j HSNo_Quaternion_j (from left to right).
We will
prove 0 + - ((- j ') * (- j)) = - 1.
rewrite the current goal using conj_HSNo_j (from left to right).
We will
prove 0 + - ((- - j) * (- j)) = - 1.
rewrite the current goal using minus_HSNo_invol j HSNo_Quaternion_j (from left to right).
We will
prove 0 + - (j * (- j)) = - 1.
rewrite the current goal using minus_mul_HSNo_distrR j j HSNo_Quaternion_j HSNo_Quaternion_j (from left to right).
We will
prove 0 + - - (j * j) = - 1.
rewrite the current goal using Quaternion_j_sqr (from left to right).
rewrite the current goal using minus_HSNo_invol 1 HSNo_1 (from left to right).
We will
prove 0 + - 1 = - 1.
An
exact proof term for the current goal is
add_HSNo_0L (- 1) L1.