We prove the intermediate
claim Li2:
OSNo i2.
We prove the intermediate
claim Li6:
OSNo i6.
We prove the intermediate
claim Li0:
OSNo i0.
We prove the intermediate
claim Li6i2:
OSNo (i6 ⨯ i2).
An
exact proof term for the current goal is
OSNo_mul_OSNo i6 i2 ?? ??.
rewrite the current goal using
OSNo_p0_i0 (from left to right).
rewrite the current goal using
mul_OSNo_proj0 i6 i2 ?? ?? (from left to right).
rewrite the current goal using
OSNo_p0_j (from left to right).
rewrite the current goal using
OSNo_p1_j (from left to right).
rewrite the current goal using
OSNo_p0_i6 (from left to right).
rewrite the current goal using
OSNo_p1_i6 (from left to right).
We will
prove 0 * j + - (0 ' * (- j)) = - 0.
rewrite the current goal using conj_HSNo_id_SNo 0 SNo_0 (from left to right).
rewrite the current goal using mul_HSNo_0L j HSNo_Quaternion_j (from left to right).
rewrite the current goal using
mul_HSNo_0L (- j) (HSNo_minus_HSNo j HSNo_Quaternion_j) (from left to right).
rewrite the current goal using minus_HSNo_0 (from left to right).
An exact proof term for the current goal is add_HSNo_0L 0 HSNo_0.
rewrite the current goal using
OSNo_p1_i0 (from left to right).
rewrite the current goal using
mul_OSNo_proj1 i6 i2 ?? ?? (from left to right).
rewrite the current goal using
OSNo_p0_j (from left to right).
rewrite the current goal using
OSNo_p1_j (from left to right).
rewrite the current goal using
OSNo_p0_i6 (from left to right).
rewrite the current goal using
OSNo_p1_i6 (from left to right).
We will
prove 0 * 0 + (- j) * j ' = - 1.
rewrite the current goal using mul_HSNo_0L 0 HSNo_0 (from left to right).
rewrite the current goal using conj_HSNo_j (from left to right).
rewrite the current goal using
minus_mul_HSNo_distrL j (- j) HSNo_Quaternion_j (HSNo_minus_HSNo j HSNo_Quaternion_j) (from left to right).
rewrite the current goal using minus_mul_HSNo_distrR j j HSNo_Quaternion_j HSNo_Quaternion_j (from left to right).
rewrite the current goal using Quaternion_j_sqr (from left to right).
rewrite the current goal using minus_HSNo_invol 1 HSNo_1 (from left to right).
An
exact proof term for the current goal is
add_HSNo_0L (- 1) (HSNo_minus_HSNo 1 HSNo_1).
∎