We will
prove p0 (i3 ⨯ i3) = p0 (- 1).
We will
prove p0 (i3 ⨯ i3) = - 1.
rewrite the current goal using
OSNo_p0_i3 (from left to right).
rewrite the current goal using
OSNo_p1_i3 (from left to right).
rewrite the current goal using mul_HSNo_0R 0 HSNo_0 (from left to right).
We will
prove 0 + - ((- i) ' * (- i)) = - 1.
rewrite the current goal using conj_minus_HSNo i HSNo_Complex_i (from left to right).
We will
prove 0 + - ((- i ') * (- i)) = - 1.
rewrite the current goal using conj_HSNo_i (from left to right).
rewrite the current goal using minus_HSNo_invol i HSNo_Complex_i (from left to right).
We will
prove 0 + - (i * (- i)) = - 1.
rewrite the current goal using minus_mul_HSNo_distrR i i HSNo_Complex_i HSNo_Complex_i (from left to right).
We will
prove 0 + - - i * i = - 1.
rewrite the current goal using
minus_HSNo_invol (i * i) (HSNo_mul_HSNo i i HSNo_Complex_i HSNo_Complex_i) (from left to right).
rewrite the current goal using Quaternion_i_sqr (from left to right).
We will
prove 0 + - 1 = - 1.
An
exact proof term for the current goal is
add_HSNo_0L (- 1) L1.