We prove the intermediate
claim Li3:
OSNo i3.
We prove the intermediate
claim Li0:
OSNo i0.
We prove the intermediate
claim Li1:
OSNo i1.
We prove the intermediate
claim Li0i3:
OSNo (i0 ⨯ i3).
An
exact proof term for the current goal is
OSNo_mul_OSNo i0 i3 ?? ??.
rewrite the current goal using
OSNo_p0_i (from left to right).
rewrite the current goal using
mul_OSNo_proj0 i0 i3 ?? ?? (from left to right).
rewrite the current goal using
OSNo_p0_i3 (from left to right).
rewrite the current goal using
OSNo_p1_i3 (from left to right).
rewrite the current goal using
OSNo_p0_i0 (from left to right).
rewrite the current goal using
OSNo_p1_i0 (from left to right).
We will
prove 0 * 0 + - ((- i) ' * 1) = - i.
rewrite the current goal using mul_HSNo_0L 0 HSNo_0 (from left to right).
rewrite the current goal using conj_minus_HSNo i HSNo_Complex_i (from left to right).
rewrite the current goal using conj_HSNo_i (from left to right).
rewrite the current goal using minus_HSNo_invol i HSNo_Complex_i (from left to right).
We will
prove 0 + - (i * 1) = - i.
rewrite the current goal using mul_HSNo_1R i HSNo_Complex_i (from left to right).
An
exact proof term for the current goal is
add_HSNo_0L (- i) (HSNo_minus_HSNo i HSNo_Complex_i).
rewrite the current goal using
OSNo_p1_i (from left to right).
rewrite the current goal using
mul_OSNo_proj1 i0 i3 ?? ?? (from left to right).
rewrite the current goal using
OSNo_p0_i3 (from left to right).
rewrite the current goal using
OSNo_p1_i3 (from left to right).
rewrite the current goal using
OSNo_p0_i0 (from left to right).
rewrite the current goal using
OSNo_p1_i0 (from left to right).
We will
prove (- i) * 0 + 1 * 0 ' = - 0.
rewrite the current goal using conj_HSNo_id_SNo 0 SNo_0 (from left to right).
rewrite the current goal using mul_HSNo_0R 1 HSNo_1 (from left to right).
rewrite the current goal using minus_HSNo_0 (from left to right).
rewrite the current goal using
mul_HSNo_0R (- i) (HSNo_minus_HSNo i HSNo_Complex_i) (from left to right).
An exact proof term for the current goal is add_HSNo_0L 0 HSNo_0.
∎